25.12=3.14(x^2)

Solution for 25.12=3.14(x^2) equation:

25.12=3.14(x^2)

We move all terms to the left:

25.12-(3.14(x^2))=0

We get rid of parentheses

-3.14x^2+25.12=0

a = -3.14; b = 0; c = +25.12;
Δ = b2-4ac
Δ = 02-4·(-3.14)·25.12
Δ = 315.5072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{315.5072}}{2*-3.14}=\frac{0-\sqrt{315.5072}}{-6.28}
=-\frac{\sqrt{}}{-6.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{315.5072}}{2*-3.14}=\frac{0+\sqrt{315.5072}}{-6.28}
=\frac{\sqrt{}}{-6.28}
$